题目浅析

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  • 简单地说,就是给一个二叉树和一个值 target,删除树中所有与 target 相等值的点。

思路分享

代码解答(强烈建议自行解答后再看)

  • 参考题解
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# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def removeLeafNodes(self, root: Optional[TreeNode], target: int) -> Optional[TreeNode]:
if not root:
return None
root.left = self.removeLeafNodes(root.left, target)
root.right = self.removeLeafNodes(root.right, target)
if not root.left and not root.right and root.val == target:
return None
return root