题目浅析

  • 想查看原题可以点击题目链接

  • 简单地说,就是给一个二叉树,现在要在其中找到一条最长的路径,路径中要求值相同。

思路分享

代码解答(强烈建议自行解答后再看)

  • 参考题解
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# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def longestUnivaluePath(self, root: Optional[TreeNode]) -> int:
ans = 0
def dfs(root: Optional[TreeNode]) -> int:
if not root:
return -1
left = dfs(root.left) + 1
right = dfs(root.right) + 1

if root.left and root.val != root.left.val:
left = 0
if root.right and root.val != root.right.val:
right = 0

cur = left + right
nonlocal ans
if ans < cur:
ans = cur

return max(left, right)

dfs(root)
return ans